Question

Calculate the percentage composition of the
following compounds :
(i) Urea CO(NH2)2
(ü) Copper sulphate CuSO4.5H20.​

Answer 1

Answer:

% composotion of an element in a compound is

% composotion of an element in a compound is Atomic massofelement*100/Molecularmass of compound

Mol mas of urea =60

% of C in urea = 12*100/60 =20%

% of O inurea = 16*100/60 =26.6%

Two nitrogen atoms and four hydrogen atoms

% of N in urea = 14*2*100/60=46.6%

% of H in urea = 1*4*100/60=6.6%

Similarly other compounds composition can be calculated.

Answer 2

Answer:

% composotion of an element in a compound is

% composotion of an element in a compound is Atomic massofelement*100/Molecularmass of compound

Mol mas of urea =60

% of C in urea = 12*100/60 =20%

% of O inurea = 16*100/60 =26.6%

Two nitrogen atoms and four hydrogen atoms

% of N in urea = 14*2*100/60=46.6%

% of H in urea = 1*4*100/60=6.6%

Similarly other compounds composition can be calculated.

Explanation: