Calculate the percentage composition of the following
ii) Calcium in calcium carbonate (CaCO3).
[Atomic mass = Ca = 40, C = 12; O =16; N = 14; H = 1 ] ii
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Given, Ca=40
from the question, CaCO³=40+(12+16)×3 = 124
.
. . Composition percentage = calcium
—------------------------------
calcium carbonate
= __40_____×100%
124
= ____ 10____×100%
31
= 32.25
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