Question

Calculate the percentage composition of the hydrogen and oxygen in water. [H=1,O =16]

Answer 1

Answer:

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Molecular mass of H₂O = 2 + 16 = 18g) As there are 2 hydrogen atoms in 1 mole of water; Molar mass of H in 1 mole of H₂O = 1 × 2= 2g Therefore %age of Hin H₂O = x 100 = 11.1% Also molar mass of O in 1 mole of H₂O = 16g Therefore %age of O in H₂O = x 100 = 88.9%

Answer 2

Answer:

Molecular mass of H2 O=2+16=18g

As there are 2 hydrogen atoms in 1 mole of water ; Molar mass of H in 1 mole of H 2 O=1×2=2g

Therefore %age of H in H2 O =  2/18  ×100=11.1%

Also molar mass of O in 1 mole of H2O =16g

Therefore %age of O in H2 O = 16/18  *100=88.9%

Explanation:

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