Question

calculate the percentage composition of water of crystallization in FeSo4. 7H2O

Answer 1

Answer:

Sorry I am in ICSE

Answer 2

Answer:

atomic mass of Fe = 56 g/mol

atomic mass of S = 32 g/mol

atomic mass of O = 4 g/mol

atomic mass of H = 1 g/mol

now,

molar mass of FeSO4.7H2O = 56 + 32 + 4 × 16 + 7 × { 2 × 1 + 16 }

= 56 + 32 + 64 + 126

= 278 g/mol

molar mass of 7H2O = 7 × { 2 ×1 + 16 } =126 g/mol

now,

% of water in FeSO.7H2O ={ molar mass of 7H2O /molar mass of FeSO4.7H2O }× 100

= { 126/278} × 100

= 12600/278

= 45.32 %