Question

calculate the percentage composition of water present in washing soda [Na2CO3*10H2O]​

Answer 1

Answer:

Given atomic masses,

Na = 23 g

C = 12 g

O = 16 g

H = 1 g

Total molar mass in Washing Soda = Na2CO3 . 10H20

= (23*2) + 12 + (16*3) + 10 [ (1*2) + 16 ] g

= 46+12+48+180 g

= 286 g

Percentage Composition of water in Washing Soda = (180/286)*100%

= 62.937%

I hope this helps.