Question

calculate the percentage composition of zinc nitrate where, zinc is 65 nitrogen is 14 and oxygen is 16 step by step​

Answer 1

Answer:

ZnNo3 = 65+14+48

= 127 g/ mol

Percentage composition =

1. Zinc

Atomic Wt of Zn = 65 g/mol

65/127*100

= 51.18 percent

2. Nitrogen

Atomic Wt = 14 g/mol

14/127*100

= 11.02 percent

3. Oxygen

Atomic Wt = 48 g/mol

48/127*100

= 37.79 percent.