Question

Calculate
the percentage Composition urea CO(NH₂ )2 ?​

Answer 1

Answer:

46%

Explanation:

Urea= NH2- CO- NH2 And we know that Total mass of urea = 60 Mass of nitrogen = 14 Two molecules of nitrogen= 2*14= 28 Percentage of nitrogen = Mass of Nitrogen/(Urea ) x 100 = 28/60 x 100 = 46.6% Hence Percentage of nitrogen in urea is 46%

Answer 2

Answer:

C=20%

O=26.67%

N=46.67%

H=6.67%

Explanation:

percentage composition of urea:ATOMIC NUMBER OF C=12

O=16

N=12

H=1

R.M.M. of urea:-

12+16+(14×2)+(1×4)

12+16+28+4

60a.m.u.

% comp. of carbon=12/60×100=20%

% comp. of oxygen=16/60×100=26.67%

%comp. of nitrogen=28/60×100=46.67%

%comp. of hydrogen=4/60×100=6.67%