Physics, asked by elvinadsouza, 9 months ago

calculate the percentage error in kinteic energy. if percentage errorin mass and velocity are 2% & 3%? please answer me​

Answers

Answered by singhbhawana191
1

Answer:

8%

Explanation:

as kinetic energy is mv^2/2

so error is dm/m + 2dv/v

here dm/m = 2% and dv/v =3%

hence

2+ 2×3

8%

Answered by ShivamKashyap08
5

Answer:

  • The Percentage error in K.E is 8 %.

Given:

  1. Percentage error in Mass is 2 %
  2. Percentage error in velocity is 3 %

Explanation:

\rule{300}{1.5}

From the K.E formula we know,

K.E = 1 / 2 M v²

Where,

  • K.E Denotes Kinetic Energy.
  • M Denotes Mass.
  • v Denotes Velocity.

Applying Error Application in the formula,

⇒ Δ K.E / K.E = Δ M / M + 2 ( Δ v / v )

Now, from the given information in question,

  • Δ M / M = 2 %
  • Δ v / v = 3 %

⇒ Δ K.E / K.E = 2 % + 2 ( 3 % )

⇒ Δ K.E / K.E = 2 % + 2 × 3 %

⇒ Δ K.E / K.E = 2 % + 6 %

⇒ Δ K.E / K.E = 8 %

Δ K.E / K.E = 8 %

The Percentage error in K.E is 8 %.

\rule{300}{1.5}

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