calculate the percentage error in kinteic energy. if percentage errorin mass and velocity are 2% & 3%? please answer me
Answers
Answered by
1
Answer:
8%
Explanation:
as kinetic energy is mv^2/2
so error is dm/m + 2dv/v
here dm/m = 2% and dv/v =3%
hence
2+ 2×3
8%
Answered by
5
Answer:
- The Percentage error in K.E is 8 %.
Given:
- Percentage error in Mass is 2 %
- Percentage error in velocity is 3 %
Explanation:
From the K.E formula we know,
⇒ K.E = 1 / 2 M v²
Where,
- K.E Denotes Kinetic Energy.
- M Denotes Mass.
- v Denotes Velocity.
Applying Error Application in the formula,
⇒ Δ K.E / K.E = Δ M / M + 2 ( Δ v / v )
Now, from the given information in question,
- Δ M / M = 2 %
- Δ v / v = 3 %
⇒ Δ K.E / K.E = 2 % + 2 ( 3 % )
⇒ Δ K.E / K.E = 2 % + 2 × 3 %
⇒ Δ K.E / K.E = 2 % + 6 %
⇒ Δ K.E / K.E = 8 %
⇒ Δ K.E / K.E = 8 %
∴ The Percentage error in K.E is 8 %.
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