Question

calculate the percentage error in kinteic energy. if percentage errorin mass and velocity are 2% & 3%? please answer me​

Answer 1

Answer:

8%

Explanation:

as kinetic energy is mv^2/2

so error is dm/m + 2dv/v

here dm/m = 2% and dv/v =3%

hence

2+ 2×3

8%

Answer 2

Answer:

• The Percentage error in K.E is 8 %.

Given:

1. Percentage error in Mass is 2 %
2. Percentage error in velocity is 3 %

Explanation:

$\rule{300}{1.5}$

From the K.E formula we know,

⇒ K.E = 1 / 2 M v²

Where,

• K.E Denotes Kinetic Energy.
• M Denotes Mass.
• v Denotes Velocity.

Applying Error Application in the formula,

⇒ Δ K.E / K.E = Δ M / M + 2 ( Δ v / v )

Now, from the given information in question,

• Δ M / M = 2 %
• Δ v / v = 3 %

⇒ Δ K.E / K.E = 2 % + 2 ( 3 % )

⇒ Δ K.E / K.E = 2 % + 2 × 3 %

⇒ Δ K.E / K.E = 2 % + 6 %

⇒ Δ K.E / K.E = 8 %

⇒ Δ K.E / K.E = 8 %

∴ The Percentage error in K.E is 8 %.

$\rule{300}{1.5}$