Question

Calculate the percentage increase in length of a wire of diameter 2.2 m stretched by a load of 100g. Young's modulus of wire is 12.5 × 10^10 N/m^2​

Answer 1

Hi,

Here is your answer,

Here,

           2r = 2.5 mm = 0.25

or         r = 0.125 cm

 Therefore,            a = πr² = 22/7 × (0.125)² sq.cm

                       F = 10 Kg = 100 × 1000 g 

                       F = 10 × 1000 × 980 dyne 

                       Y = 12.5 × 10¹¹ dyne/sq.cm

 As,                         →  Y= F × l/ a ×Δl

∴   ΔL/L = F/aY

Hence, Percentage increases in length

     = ΔL/L × 100 = F/aY × 100

     = (100×1000×980) × 7 × 100/ 22 × (0.125)² × 125 × 10¹¹  

     = 0.1812 Percent 

Hope it helps you !

Answer 2

what the heck is 5his question