Question

Calculate the percentage increase in the length of a wire of diameter 2mm stretched by a force

of 1kg F. Young’s modulus of the material of wire is 15 X 1010N/m2​

Answer 1

Answer:

Don't know what to do with

Answer 2

Explanation:

Given that,

Young’s modulus of the material Y=15×10

10

N/m

Diameter d=2mm

Radius r=0.02m

Force F=1kg

Now,

Y=

l

Δl

A

F

l

Δl

=

A×Y

F

l

Δl

×100=[

3.14×(0.002)

2

×15×10

10

9.8

]×100

l

Δl

×100=[

3.14×4×10

−6

×15×10

10

9.8

]×100

l

Δl

×100=[0.052017×10

−4

]×100

l

Δl

×100=0.00052 %

Hence, the percentage increase in length of a wire is 0.00052 %