Calculate the percentage loss of mass hydrated copper sulphate when it is completely dehydrated [Cu=64,S=32,O=16,H=1]
Answers
Hey Friend,
Hydrated copper (II) sulphate - CuSO4.xH2O
Considering that the Salt is completely hydrated... x=5
Hydrated copper (II) sulphate - CuSO4.5H2O
Dehydrated copper (II) sulphate - CuSO4
Molecular weights of -
1. CuSO4.5H2O
64 + 32 + (16x4) + 5 [2 + 16]
64 + 32 + 64 + 90
250 grams
2. CuSO4
64 + 32 + (16x4)
64 + 32 + 64
160 grams
Therefore,
Difference in the molecular weights... 250 - 160 = 90 grams
Percentage loss = Difference in weights
-------------------------------------- x 100
Molecular weight of intial compound
Percentage loss = 90 x 100 / 250
= 36 %
Therefore, the percentage loss in the mass when hydrated copper sulphate is completely dehydrated is 36 %.
Hope it helps!