Question

Calculate the percentage loss of mass of decahydrate sodium sulphate when it is completey dehydrated.

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Answer 1

$❥︎Answer❀✿°᭄$

The molecular weight of water H2O=2(1)+16=18.

When 1 mole of CuSO4⋅5H2O is heated, 5 moles of water are lost.

The molecular weight of CuSO4⋅5H2O=64+32+4(16)+5(18)=250 g/mol

Mass of water lost =5(18)=90 g

Percentage loss of mass of CuSO4⋅5H2O=25090×100=36 %.

$# ItzAditya$

Answer 2

The molecular weight of water H

2

O=2(1)+16=18.

When 1 mole of CuSO

4

⋅5H

2

O is heated, 5 moles of water are lost.

The molecular weight of CuSO

4

⋅5H

2

O=64+32+4(16)+5(18)=250 g/mol

Mass of water lost =5(18)=90 g

Percentage loss of mass of CuSO

4

⋅5H

2

O=

250

90

×100=36 %

36% is your answer

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