Chemistry, asked by adityatanu8034, 5 hours ago

calculate the percentage loss of mass of hydrated copper[||] sulphate [ Cuso4.5H2O​

Answers

Answered by rajeebsc001
1

Answer:

Percentage of loss in the mass

when hydrated Copper Sulphate is completely dehydrated is

36 %.

The molecular weight of water,

H2O=2(1)+16=18.

When 1 mole of CuSO 4⋅5H2O is heated, 5 moles of water are lost.

The molecular weight of,

CuSO 4⋅5H2O =64+32+4(16)+5(18)

=250 g/mol

Mass of water lost =5(18)=90 g

Percentage loss of mass of,

CuSO 4⋅5H2O = 90/250 ×100

=36 %.

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