Chemistry, asked by rekhaj44249, 9 months ago

Calculate the percentage loss
of mass
of hydrated
Copper (II) sulphate [CuSo4.5 H₂o] when it is completely
dehydrated. [ CuSo4. 5H₂O → CuSo4 + 5 H₂O]

Answers

Answered by Phaneendhar

1

Answer:

42.9(approx)

Explanation:

Mass of CuSO4.5H2O=210

Mass of 5H2O=90

Percentage loss in weight=(90/210)×100=

42.9percent(approximately)

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