Calculate the percentage loss
of mass
of hydrated
Copper (II) sulphate [CuSo4.5 H₂o] when it is completely
dehydrated. [ CuSo4. 5H₂O → CuSo4 + 5 H₂O]
Answers
Answered by
1
Answer:
42.9(approx)
Explanation:
Mass of CuSO4.5H2O=210
Mass of 5H2O=90
Percentage loss in weight=(90/210)×100=
42.9percent(approximately)
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