Chemistry, asked by zuhasyed, 2 months ago

Calculate the percentage loss of mass of hydrated copper[II]sulphate [CuSO4.5H2O]
when it is completely dehydrated. [CuSO4.5H2O → CuSO4 + 5H2O]
[At. wts. are Cu = 64, S = 32, O = 16, H = 1].

Answers

Answered by vvsbs2542

1

Answer:

CuSO4.5H2O → CuSO4 + 5H2O]

[At. wts. are Cu = 64, S = 32, O = 16, H = 1].

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