Question

calculate the percentage of all the elements in the given compounds HNO3​

Answer 1

Explanation:

H = 1 × 1 = 1 g

N =1 × 14 =14 g

O = 3 × 16 = 48 g  

Adding these total

1 + 14 + 48 = 63 g

% H = 1 /63

# 1/63 = 1.5% H

% N = 14 /63

# 14/63 = 22% N

% O = 48 /63

# 48/63 = 76% O