Question

calculate the percentage of C H and O in C2H5OH​

Answer 1

Answer:

The percentage composition of ethanol ( C2H5OH ) is: 52.2% of Carbon, 13.0% of Hydrogen, and 34.8% of Oxygen

Explanation:

______@Deepak Razput

Answer 2

Explanation:

• C2H50H

Compound contains

• Two atoms of carbon
• Six atoms of hydrogen
• One atom of oxygen

Total no. of atoms = 9

% of Carbon =

$= \frac{no. \: of \: atoms\: of \: carbon}{total \: no. \: of \: atoms} \times 100$

$= \frac{2}{9} \times 100$

$= 22.22\%$

% of Hydrogen =

$= \frac{no. \: of \: atoms \: of \: hydrogen}{total \: no. \: of \: atoms} \times 100$

$= \frac{6}{9} \times 100$

$= 66.66\%$

% of Oxygen =

$= \frac{no. \: of \: atoms \: of \: oxygen}{total \: no. \: of \: atoms} \times 100$

$= \frac{1}{9} \times 100$

$= 11.11\%$