Calculate the percentage of carbon, hydrogen and nitrogen in urea. [5]
[ At mass: N= 14, H=1, C= 12 ]
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Explanation:
urea = NH2-CO-NHè
Total Mass =60
Mass of nitrogen =14,2 molecules hence
m=28
N%=mass of nitrogen*100
mass of urea
=28*100
60
N%=46.6%
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Explanation:
Formula of urea H2NCONH2
One hydrogen's atomic mass=1
One carbon's atomic mass=12
One Nitrogen's atomic mass=14
One oxygen's atomic mass is =16
Total 4+28+12+16=60
percentage of carbon= 1200/60=20%
percentage of hydrogen=400/60=6.66%
percentage of nitrogen=2800/60=46.6%
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