calculate the percentage of composition of Magnesium Carbonate (Mg=24,C=12,O=16)
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⚛Answer :-
- Magnesium - 28.57 %
- Carbon - 14.28%
- Oxygen - 57.14%
Given to calculate the Percentage of composition of Magnesium carbonate (MgCO₃)
⚛SOLUTION :-
Percentage composition of each element can be calculated by
Percentage composition = Mass of element/Total weight of compound × 100
So, Firstly Lets calculate compound weight (MgCO₃)
⚛ Atomic mass of Magnesium(Mg) = 24
Atomic mass of Carbon (C) = 12
Atomic mass of Oxygen (O) = 16
MgCO₃ = Mg + C + 3 atoms of Oxygen
= 24 + 12 + 3(16)
= 24+12 +48
= 84
Weight of (MgCO₃) is 84
Percentage composition of Magnesium = 24/84 × 100
= 2/7 × 100
= 200/7
= 28.57 %
Percentage composition of Carbon = 12/84 × 100
= 1/7 × 100
= 100/7
= 14.28%
Percentage composition of Oxygen₃ = 48/84 ×100
= 4/7 ×100
= 4×100/7
=400/7
= 57.14%
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