Question

calculate the percentage of composition of sodium from sodium nitrate​

Answer 1

Explanation:

The percent composition in sodium nitrate has been 27.05% Na, 16.47% N, and 56.47% Oxygen.

Sodium nitrate has is the molecular compound that has been consisted of sodium, nitrogen, and oxygen.

1 mole of sodium nitrate has consisted of 1 sodium atom, 1 nitrogen, and 3 oxygen atoms.

The molecular mass of sodium nitrate has been:

\rm NaNO_3NaNO

3

= Mass of Na + Mass of N + Mass of O.

Molecular mass of \rm NaNO_3NaNO

3

= 23 + 14 + (16 × 3) g/mol

Molecular mass of \rm NaNO_3NaNO

3

= 85 g/mol.

The percent composition has been :

Percent composition = \rm \dfrac{Mass}{Total\;mass}\;\times\;100

Totalmass

Mass

×100

Percent composition of sodium = \rm \dfrac{23}{85}\;\times\;100

85

23

×100

Percent composition of sodium = 27.05 %

Percent composition of nitrogen = \rm \dfrac{14}{85}\;\times\;100

85

14

×100

Percent composition of nitrogen = 16.47 %.

Percent composition of Oxygen = \rm \dfrac{48}{85}\;\times\;100

85

48

×100

Percent composition of Oxygen = 56.47%.

The percent composition in sodium nitrate has been 27.05% Na, 16.47% N, and 56.47% Oxygen.