calculate the percentage of deutrium in heavy water.
please answer with explanation
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formula of heavy water = D2O
atomic mass of Deuterium = 2g/mol
so, molar mass of D2O
= 2 × 2 + 16 = 20g/ mol
now percentage of Deuterium =2× atomic mass of D/molar mass of D2O ×100
= 2×2 /20 × 100
= 20 %
atomic mass of Deuterium = 2g/mol
so, molar mass of D2O
= 2 × 2 + 16 = 20g/ mol
now percentage of Deuterium =2× atomic mass of D/molar mass of D2O ×100
= 2×2 /20 × 100
= 20 %
laharipragna:
Oooo got it
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