Question

Calculate the percentage of Fe in Fe2(CO3)3

Answer 1

% Fe = 2 x 55.847 x 100/ 291.718=38.29  

% C = 3 x 12.011 x 100/ 291.718=12.35  

% O = 9 x 15.999 x 100/ 291.718=49.36

Answer 2

Given:

Formula of compound= $Fe_2(CO_3)_3$

To find:

Percentage of Fe in  $Fe_2(CO_3)_3$

Formula to be used:

% Composition by mass $\frac{Molar mass of element \times Number of element}{Molar mass of compound} \times 100$

Calculation:

The molar mass of the compound  $Fe_2(CO_3)_3$ is:

2 (Fe) = 2 (55.845) = 111.69

3 (C) = 3 (12.011) = 36.033

9 (O) = 9(16) = 144

∴Molar mass of  $Fe_2(CO_3)_3$ = 111.69+36.033+144 = 291.723u

To find % composition Fe:

% Composition of Fe =  $\frac{Molar mass of element \times Number of element}{Molar mass of compound} \times 100$

% Composition of Fe = $\frac{55.845 \times 2}{291.723} \times 100$

% Composition of Fe = $\frac{111.69}{291.723}\times 100$

% Composition of Fe = 0.3828 × 100

% Composition of Fe = 38.2

Conclusion:

The percentage composition of Fe in $Fe_2(CO_3)_3$ is 38.2%

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