calculate the percentage of hydrolysis of ammonium acetate. The dissociation constant for Nh4OH is 1.8 x 10^-5 and that of CH3COOH is 1.8 x 10^-5
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this is the answer hope u like it
Explanation:
pH=
2
1
[p
K
w
+p
K
a
−p
K
b
]
=
2
1
[14−log(4×10
−5
+log(1.8×10
−5
)]
pH=3.65 .
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