Question

calculate the percentage of lead in Pb3O4 i need it step by step​

Answer 1

Answer:

Molar mass of Pb3O4 = 685.59 g/mol

atomic mass of lead = 207.2u

so percentage of lead = product of number of lead atoms × atomic mass of one lead atom ×100 divided by total molecular mass of the compound given

$\frac{3 \times 207.2 \times 100}{685.59}$

= 90.66%