Question

Calculate the percentage of monochloro isomers produces during the chlorination of tertiary butane

Answer 1

Number of mono chloro isomers depends upon the types of hydrogen atoms present in the substate alkane. The structure of 2−methylbutane is

C

d

H

3

−

C

c

H

2

−

H

b

a

C

H

3

∣

C

−

C

a

H

3

Because of the presence of four types of hydrogen, it gives four+two(d and l forms) = six monochloro products on monochlorination as

CH

3

−CH

2

CH

3

∣

C

H

−CH

3

Cl

2

hv

d and l forms

1-chloro-2-methyl butane

CH

3

CH

2

C

˙

H−CH

2

Cl

+

2−chloro−2−methylbutane

CH

3

−CH

2

−

CH

3

∣

C

∣

−

Cl

CH

3

+

2−chloro−3−methylbutane

CH

3

−

Cl

∣

C

˙

H−CH(CH

3

)

2

+

1−chloro−3−methylbutane

CH

2

ClCH

2

−

CH

3

∣

C

H

−CH

3