Calculate the percentage of nitogen in urea NH₂CONH₂.
Given : R.A.M. of N = 14, C = 12, O = 16, H = 1
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- Relative molecular mass of urea NH₂CONH₂ is :
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∴ R.M.M. = 60
- Percentage of Nitrogen = Wt. of nitrogen/Total wt. of urea ༝ 100
➢ 28/60 ༝ 100
➢ 46.666 or 46.67%
☯ Therefore,
- Hence, the nitrogen is 46.67%.
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