Question

Calculate the percentage of nitrogen and carbon in urea.
NH2CONH2 [3]

Answer 1

Total number of Nitrogen atoms=2

Total number of Hydrogen atoms=4

Total number of Carbon atoms=1

Total number of Oxygen atoms=1

Molar mass of N atoms=2×14=28

Molar mass of H atoms=1×4=4

Molar mass of C atoms=12×1=12

Molar mass of O atoms=16×1=16

Molecular Mass of NH2CONH2=28+4+12+16=60

Percentage of Nitrogen=28/60×100=46.67%

Percentage of Carbon=12/60×100=20%

Answer 2

Answer:

Percentage of Carbon: 20%

Percentage of Nitrogen: 46.67%

Explanation:

Firstly, we calculate the molecular mass of Urea, $NH_{2}CONH_{2}$.

= (Atomic masses: Nitrogen = 14; Hydrogen = 1; Carbon = 12 Oxygen = 16)

= 14 + 2(1) + 12 + 16 + 14 + 2(1)

= 60.

We have found the Molecular Mass of Urea

Now, we need, percentage of (i) Carbon, and (ii) Nitrogen.

(i) $\frac{12}{60}$ × 100 = 20%

(ii) $\frac{28}{60}$ × 100 = 46.67%

The Percentage of Carbon: 20%,

The Percentage of Nitrogen: 46.67%

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