Question

Calculate the percentage of nitrogen in ammonium nitrate [NH4NO3]
[N=14, H=1, O=16 ]




Please tell answer please

Answer 1

Answer:

Percent composition of N is 35% . Percent composition of H is 5% .

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Answer 2

$\sf \Large Solution!!$

$\sf \to Mass\:of\:NH_{4}NO_{3}=14\times 2+1\times 4+16\times 3$

$\sf \to Mass\:of\:NH_{4}OH_{3}=80$

$\sf \to Weight\:of\:nitrogen=2\times 14=28$

$\sf \to \%\:of\:nitrogen=\frac{28}{80}\times 100$

$\sf \boxed{\bigstar \%\:of\:nitrogen=35\%}$

Thanks for asking!! :)