Calculate the percentage of nitrogen in urea CO(NH₂)₂.
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3
Answer:
Given Urea= NH2- CO- NH2 And we know that Total mass of urea = 60 Mass of nitrogen = 14 Two molecules of nitrogen= 2*14= 28 Percentage of nitrogen = Mass of Nitrogen/(Urea ) x 100 = 28/60 x 100 = 46.6% Hence Percentage of nitrogen in urea is 46% .
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Explanation:
Answered by
0
Answer:
46.66%
Explanation:
percentage of nitrogen = mass of nitrogen/total mass × 100
= 14×2/60×100
=28/60×100
= 46.66%
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