Question

calculate the percentage of nitrogen in urea co (nh2)2 (atomic mass n=14, c=12, h=1)​

Answer 1

Answer:

Here is ur answer bro

Step-by-step explanation:

Given Urea= NH2- CO- NH2 And we know that Total mass of urea = 60 Mass of nitrogen = 14 Two molecules of nitrogen= 2*14= 28 Percentage of nitrogen = Mass of Nitrogen/(Urea ) x 100 = 28/60 x 100 = 46.6% Hence Percentage of nitrogen in urea is 46% Option A is the right answer.

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Answer 2

ANSWER:Here is ur answer bro

Step-by-step explanation:

Given Urea= NH2- CO- NH2 And we know that Total mass of urea = 60 Mass of nitrogen = 14 Two molecules of nitrogen= 2*14= 28 Percentage of nitrogen = Mass of Nitrogen/(Urea ) x 100 = 28/60 x 100 = 46.6% Hence Percentage of nitrogen in urea is 46% Option A is the right answer.