Question

Calculate the percentage of oxygen in a compound containing 76.6% of Carbon and 6.38% of
Hydrogen.​

Answer 1

Answer:

Explanation:

Carbon % = 76.5%

Hydrogen% = 6.38%

Oxygen% = 100 - (76.5 + 6.38)

 = 100 - 82.88

 = 17.12%

Now, Refers to the attachment for the Empirical Formula Chart.

Empirical Formula is C₆H₆O.

Empirical Formula Mass = 12 × 6 + 1 × 6 + 16

= 94 g

Molecular Mass = 2 × Vapor Density

∴ Molecular Mass = 2 × 47

∴ Molecular Mass = 94 g.

∴ n = Molecular Mass/Empirical Formula Mass

  = 94/94

  = 1

∴ Molecular Formula = 1 × C₆H₆O

  = C₆H₆O