Question

calculate the percentage of oxygen in Al2(SO4)3
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Answer 1

the total no of atoms are seventeen and the no of oxygen atoms are 12 so dividing 12 by seventeen and multiplying the answer with 100

$\frac{12}{17} X100=70.581 %$%

the answer is 70.581%

hope that clears your doubt have a nice day wish you success and may your curiosity increase

Answer 2

Molar mass of the compounds= 2(27)+ 3{32+4(16)}

= 342 amu

Total mass of oxygen in the compound = 4(16)x3 = 192 amu

Percentage of oxygen = 192/342 x 100 = 56.14%

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