Question

Calculate the percentage of Oxygen in C2H4O2. 2H2O

Answer 1

Explanation:

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Answer 2

Answer:

The percentage of oxygen present in C₂H₄O₂.2H₂O is 61.5%.

Explanation:

Given,

The compound C₂H₄O₂.2H₂O

To find,

The percentage of oxygen present in C₂H₄O₂.2H₂O

Calculation,

The atomic mass of carbon(C) is 12.

The atomic mass of Hydrogen(H) is 2

The atomic mass of Oxygen(O) is 16

Now,

The molecular mass of Carbon present in C₂H₄O₂.2H₂O is 12 × 2 = 24

The molecular mass of Hydrogen present in C₂H₄O₂.2H₂O is 2 × 8 = 16

The molecular mass of Oxygen present in C₂H₄O₂.2H₂O is 16 × 4 = 64

Hence, the total molecular mass of C₂H₄O₂.2H₂O is (24 + 16 + 64) = 104

The percentage of oxygen present in C₂H₄O₂.2H₂O is:

$\frac{The \ molecular \ mass \ of \ oxygen \ in \ C_2H_4O_2.2H_2O}{The \ total \ molecular \ mass \ of \ C_2H_4O_2.2H_2O } \times 100$

⇒ The percentage of oxygen present in C₂H₄O₂.2H₂O = 64/104 × 100

Therefore, the percentage of oxygen present in C₂H₄O₂.2H₂O is 61.5%

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