Question

Calculate the percentage of oxygen in CaCO3

Answer 1

Answer:

48%

Explanation:

Mass of calcium present=(1*40)amu=40amu

Mass of carbon present=(1*12)amu=12amu

Mass of oxygen present=(3*16)amu=48amu

Total mass of 1 molecule=(40+12+48)amu=100amu

Percentage of oxygen=(48/100*100)%=48%

Hope it helps