Question

Calculate the percentage of oxygen in k2Cr2O7?(atomic masses:k=39u,Cr=52u, and O=16u)

Answer 1

38.070% percentage of oxygen in k2Cr2O7?(atomic masses:k=39u,Cr=52u, and O=16u)

Answer 2

Percentage of oxygen in $K_2Cr_2O_7$ is 38.1%

Explanation:

To calculate the mass percentage ,we use the formula:

$\text{Mass percent}=\frac{\text{Mass of element}}{\text{Molar mass of compound}}\times 100$

Mass of oxygen = $7\times 16=112g$

Mass of $K_2Cr_2O_7$ = $2\times 39+2\times 52+6\times 17=294g$

Putting values in above equation, we get:

$\text{Mass percent of oxygen}=\frac{112g}{294g}\times 100=38.1\%$

Percentage of oxygen in $K_2Cr_2O_7$ is 38.1 %

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