calculate the percentage of phosphorus in calcium phosphate of carbon and nitrogen .( nitrogen = 14 calcium = 40 ,hydrogen is equal to 1, silicon is equal to 28 chromium is equal to 52 , oxygen is equal to 16 Phosphorus is equal to 31 and carbon is equal to 12
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Answer:
20% (approx.)of phosphorous is present.
Accurately is 20.6451612903%
Explanation:
Ca3(PO4)2 is the formula.
Total mass= (40×3)+((31+(16×4))×2) amu
=120+(31+64)×2 amu
=120+190 amu
=310 amu
Therefore,percentage of phosphorous in Ca3(PO4)2 =((31×2)/310)×100%
=64/310×100%
=20.6451612903%
=20%(approx.)
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