Chemistry, asked by armyneedshelp, 4 months ago

calculate the percentage of phosphorus in the fertilizer superphosphate Ca(H₂Po₄)₂ {Ca=40, H=1, P=31, O=16}​

Answers

Answered by aditinainawat3
3

Answer:

Ca(H2Po4)2, molar mass =234gm

%of P=62*100/234=26.5%


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Answered by shivanikhosmane73
0

Answer:

Ca(H2Po4)2, molar mass =234gm

%of P=62*100/234=26.5%

Explanation:

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