calculate the percentage of phosphorus in the fertilizer superphosphate Ca(H₂Po₄)₂ {Ca=40, H=1, P=31, O=16}
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Answer:
Ca(H2Po4)2, molar mass =234gm
%of P=62*100/234=26.5%
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Answer:
Ca(H2Po4)2, molar mass =234gm
%of P=62*100/234=26.5%
Explanation:
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