Calculate the percentage of pure aluminum in 10kg of aluminium oxide [Al2O3] of 90% purity .[ Al=27,O=16]
Answers
Answered by
75
Al2O3= 27*2+16*3=54+48=102g.
102g Al2O3 contains 54g of pure Al
9000g Al2O3 contains ?
(54*9000)/102 =4764.70g or 4.76470kg
% of pure Al2O3 = (4.764*100)/100= 47.64%
102g Al2O3 contains 54g of pure Al
9000g Al2O3 contains ?
(54*9000)/102 =4764.70g or 4.76470kg
% of pure Al2O3 = (4.764*100)/100= 47.64%
Answered by
11
Answer:
Al2O3= 27*2+16*3=54+48=102g.
102g Al2O3 contains 54g of pure Al
9000g Al2O3 contains ?
(54*9000)/102 =4764.70g or 4.76470kg
% of pure Al2O3 = (4.764*100)/100= 47.64%
Explanation:
Similar questions