Calculate the percentage of sodium and oxygen in sodium carbonate. [Na=23,O=16 C=12]
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Answer:
percentage of sodium (Na) in sodium carbonate [Na2CO3] =46/106×100 = 43.40% percentage of carbon (C) in sodim carbonate [Na2CO3] =12/106×100 = 11.32% percentage of oxygen (O) in sodium carbonate [Na2CO3] = 48/106×100 = 45.28%
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Answer:
106
Explanation:
23×2 + 12+ 16×3= 106
Na2co3
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