Calculate the percentage of water of crystallisation in MgSO4.7H2O.
Answers
Answered by
0
Answer:
Relative molecular mass of MgSO4.7H2O
= 24+32+16×4+7×(2+16)
= 24 +32+64+126
=246
246g of Epsom salt contains 126g of water
∴ 100g will contain 126×100246
= 12600246
= 51.21gofH2O
∴ The % of H2OinMgSO4.7H2O = 51. 21
HOPE IT HELPS YOU
PLS MARK ME AS BRANILIEST
Answered by
0
Answer:
It's total mass is 24+32+64+126g
=246g
here H2O remains 126 g
your ans is (126/246)*100
51.21%
Is it ok?
inform me
Similar questions