Question

Calculate the percentage of water of crystallisation in MgSO4.7H2O.
（b)Find the empirical formula of a
substance which has the following
percentage composition by mass
（sodium
＝18.2%,sulphur 12.7%
19.1%,water of crystallisation
50%)​

Answer 1

Answer:

Relative molecular mass of MgSO4.7H2OMgSO4.7H2O 

= 24+32+16×4+7×(2+16)24+32+16×4+7×(2+16) 

= 24 +32+64+126 

=246 

246g of Epsom salt contains 126g of water 

∴∴ 100g will contain 126×100246126×100246 

= 1260024612600246 

= 51.21gofH2O51.21gofH2O 

∴∴ The %ofH2OinMgSO4.7H2O%ofH2OinMgSO4.7H2O = 51. 2

Answer 2

Answer:

Relative molecular mass of MgSO4.7H2OMgSO4.7H2O  

= 24+32+16×4+7×(2+16)24+32+16×4+7×(2+16)  

= 24 +32+64+126  

=246  

246g of Epsom salt contains 126g of water  

∴∴ 100g will contain 126×100246126×100246  

= 1260024612600246  

= 51.21gofH2O51.21gofH2O  

∴∴ The %ofH2OinMgSO4.7H2O%ofH2OinMgSO4.7H2O = 51. 2

Explanation:

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