Chemistry, asked by roverdnn, 1 month ago

Calculate the percentage of water of crystallisation in hydrated copper (II) sulphate [Cu = 64, S = 32, O = 16, H = 1] [Show complete calculation]
please full explanation​

Answers

Answered by xesharine4
0

Explanation:

The molecular weight of water H

2

O=2(1)+16=18g/mol.

The molecular weight of copper sulphate pentahydrate CuSO

4

.5H

2

O=64+32+4(16)+5(18)=250g/mol.

The percentage of water of crystallization in CuSO

4

.5H

2

O=

250

5×18

×100=36%

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