Question

calculate the percentage of water of crystallization in white vitriol whose formula is ZnSO4.7H2O

Answer 1

Hi.

Here is your answer---

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Molecular mass of White Vitriol = 65 + 32 + 16 × 4 + 7(1 × 2 + 16)
                                                  =  97 + 64 + 126
                                                  = 287 grams.

Mass of Water of crystallization in White Vitriol = 7 × 18
                                                                          = 126 grams.
Using the Formula,

 % of Water of Crystallization
= (Mass of Water of Crystallization/Mass of White Vitriol) × 100
                                              = (126/287) × 100
                                              = 43.91%.

Thus, the % of Water of Crystallization in White Vitriol is 43.91%.

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Hope it helps.

Have a nice day.

Answer 2

Answer:

Explanation:

Hi.

Here is your answer---

___________________

Molecular mass of ZnSO4.7H2O  = 65 + 32 + 16 × 4 + 7(1 × 2 + 16)

                                                 =  97 + 64 + 126

                                                 = 287 grams.

Mass of Water of crystallization in  ZnSO4.7H2O = 7 × 18

                                                        which is  = 126 grams.

Using this Formula,

          ↓

 % of Water of Crystallization

= (Mass of Water of Crystallization/Mass of ZnSO4.7H2O ) × 100

                                             = (126/287) × 100

                                             = 43.91%.

∴the % of water of crystallization of ZnSO4.7H2O is approximately  =44%