calculate the percentage of water of crystallization in FeSO4.(NH4)2.6 H2O
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Mass of FeSO4.(NH4)2.6 H2O = 392 g
Mass of water in it will be 108 g
% of water in FeSO4.(NH4)2.6 H2O = 108/392 × 100 = 27.55%.
Hope it works☺☺
Mass of FeSO4.(NH4)2.6 H2O = 392 g
Mass of water in it will be 108 g
% of water in FeSO4.(NH4)2.6 H2O = 108/392 × 100 = 27.55%.
Hope it works☺☺
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