Calculate the percentage of water of cyrstalisation in MgSo4 .7H2O
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MgSO₄.7H₂O = Magnesium Sulphate Heptahydrate
RAM of Mg: 24, S = 32, O = 16, H = 1
Molar Mass = 24+32+(16*4)+7(1*2+16) g
= 24+32+64+(7*18) g
= 246 g
% composition of water = Mass of water in the compound/Molar Mass*100%
= [(7*18)/246]*100%
= 51.21%
I hope this helps.
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