Calculate the percentage of water present in mgso4, 7h2o
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%H20=
(14xH)+(7xO)
______________________________ X 100
(Mg) + (S) + (4 x O) + (14 x H) + (7 x O)
Thus,
(14 x 1.008) + (7x16.0)
______________________________________ X 100
24.31 + 32.06 + (4x16.0) + (14 x 1.008) + (7x16.0)
=126.122
_____________ X 100
246.482
= 0.512 x 100
=51.2%
There is 51.2% of water is Magnesium Sulphate-7-water.
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