Calculate the perimeter of a rectangle whose area is 25x^ 2 -35x+12.?
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Answer:
25x²-35x+12=0
25x²-(20+15)x+12=0
25x²-20x-15x+12=0
5x(5x-4)-3(5x-4)=0
(5x-3) (5x-4) =0
1. 5x-3 = 0
5x = 3
x = 3/5
2. 5x-4 = 0
5x = 4
x = 4/5
length = 4/5 , breadth = 3/5
perimeter of rectangle= 2(l+b)
= 2(4/5+3/5)
= 2×7/5
= 14/5
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