Calculate the perimeter of a rectangle whose area is 25y2 - 35y + 12
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Answer:let the length and breadth of the rectangle are a and b respectively.
Area of rectangle is
25y*2-35y+12 = a×b
25y*2-20y-15y+12= a×b
(5y-3)×(5y-4) = a×b
On equating
a= 5y-3
b= 5y-4
Hence,
Perimeter of the rectangle =2 (a+b)
=2 (5y-3+5y-4)
=20y-14
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