Calculate the perimeter of:A rhombus of diagonals 8 and 10m?
Answers
Answered by
1
Answer:
Area of Rhombus = 1/2 × D1 × D2
Given,
length of diagonal 1 = 8cm
length of diagonal 2 = 10cm
A=1/2 ×d1 ×d2
A=1/2 X 8 X 10
A=1/2 X 80
A= 40cm².
Answered by
1
Answer:
The formula used is 2√p^2+q^2
Step-by-step explanation:
So the answer is 2√164=4√41
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