Calculate the period in seconds of a fan motor turns at
1200rpm.
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Answer:
The angular velocities are given as,
ω
1
=1200rpm
ω
1
=40πrad/s
ω
2
=900rpm
ω
2
=30πrad/s
The angular acceleration is given as,
α=
2
40π−30π
α=5πrad/s
2
The angle is given as,
θ=ω
1
t+
2
1
αt
2
θ=40π×2+
2
1
×5π(2)
2
θ=90πrad
The numbers of revolutions are given as,
n=
2π
90π
n=45rev
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